0=2x^2-27x+88

Solution for 0=2x^2-27x+88 equation:

0=2x^2-27x+88

We move all terms to the left:

0-(2x^2-27x+88)=0

We add all the numbers together, and all the variables

-(2x^2-27x+88)=0

We get rid of parentheses

-2x^2+27x-88=0

a = -2; b = 27; c = -88;
Δ = b2-4ac
Δ = 272-4·(-2)·(-88)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-5}{2*-2}=\frac{-32}{-4}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+5}{2*-2}=\frac{-22}{-4}
=5+1/2
$